13x^2-6x-351=0

Solution for 13x^2-6x-351=0 equation:

13x^2-6x-351=0

a = 13; b = -6; c = -351;
Δ = b2-4ac
Δ = -62-4·13·(-351)
Δ = 18288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18288}=\sqrt{144*127}=\sqrt{144}*\sqrt{127}=12\sqrt{127}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-12\sqrt{127}}{2*13}=\frac{6-12\sqrt{127}}{26}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+12\sqrt{127}}{2*13}=\frac{6+12\sqrt{127}}{26}
$